derivative f(x)=(x+6)/(x+1)

Lösung

ableitung von

f (x) = \frac{x + 6}{x + 1}

- \frac{5}{( x + 1 ) ^{2}}

Schritte zur Lösung

\frac{d}{d x} (\frac{x + 6}{x + 1})

Wende die Quotientenregel an:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x + 6 ) ( x + 1 ) - \frac{d}{d x} ( x + 1 ) ( x + 6 )}{( x + 1 ) ^{2}}

\frac{d}{d x} (x + 6) = 1

\frac{d}{d x} (x + 1) = 1

= \frac{1 \cdot ( x + 1 ) - 1 \cdot ( x + 6 )}{( x + 1 ) ^{2}}

Vereinfache

\frac{1 \cdot ( x + 1 ) - 1 \cdot ( x + 6 )}{( x + 1 ) ^{2}} : - \frac{5}{( x + 1 ) ^{2}}

= - \frac{5}{( x + 1 ) ^{2}}

\frac{d}{d x} (20 t - \frac{1}{2} g (t, x) t^{2})

d er i v a t i v e lo g_{e} (x)

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\int_{0}^{\frac{1}{2}} x ln (2 x) d x

\frac{d}{d x} (14 x^{\frac{1}{7}})