laplacetransform {e^tsin(3t)}

Lösung

laplace transformation

{e^{t} sin (3 t)}

\frac{3}{( s - 1 ) ^{2} + 9}

Schritte zur Lösung

L {e^{t} sin (3 t)}

Wende Transformationsregel an: wenn

L {f (t)} = F (s)

dann

L {e^{a t} f (t)} = F (s - a)

Für

e^{t} sin (3 t) : f (t) = sin (3 t), a = 1

= L {sin (3 t)} (s - 1)

L {sin (3 t)} : \frac{3}{s ^{2} + 9}

= \frac{3}{( s - 1 ) ^{2} + 9}

n = 1 \sum \infty \frac{ln ( 6 n )}{n}

in v erse l a pl a ce \frac{\frac{1}{2}}{s ^{2} + 2 s + 3}

3 (3 x^{2} + y^{2}) d x - 2 x y d y = 0

\frac{\partial}{\partial x} (2 e^{- 2 x y} + x y^{3})

\frac{d}{d x} (\frac{sin ( x )}{1 + tan ( x )})