y^'+4y=0

Lösung

y^{^{'}} + 4 y = 0

y = e^{- 4 t + c_{1}}

Schritte zur Lösung

y^{'} (t) + 4 y = 0

Solve separable ODE:

y = e^{- 4 t + c_{1}}

y = e^{- 4 t + c_{1}}

n = 1 \sum \infty 8 (\frac{7}{8})^{n}

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