extreme f(x)=((x^2-7))/(x+4)

Lösung

extrempunkte

f (x) = \frac{( x ^{2} - 7 )}{x + 4}

Maximum (- 7, - 14), Minimum (- 1, - 2)

Schritte zur Lösung

f^{'} (x) = \frac{x ^{2} + 8 x + 7}{( x + 4 ) ^{2}}

Intervalle finden:

Ansteigend

: - \infty < x < - 7,

Absteigend

: - 7 < x < - 4,

Absteigend

: - 4 < x < - 1,

Ansteigend

: - 1 < x < \infty

Stecke

x = - 7

\frac{x ^{2} - 7}{x + 4} : - 14

Maximum (- 7, - 14)

Stecke

x = - 1

\frac{x ^{2} - 7}{x + 4} : - 2

Minimum (- 1, - 2)

Maximum (- 7, - 14), Minimum (- 1, - 2)

e x t re m e f (x) = - 2 x^{2} + 2 x, - 3 \leq x \leq 2

e x t re m e f (x) = \frac{ln ( x )}{x ^{10}}

e x t re m e f (x, y) = \frac{7}{- 91 x ^{2} - 3 y ^{2} + 9}

e x t re m e f (x, y) = (2 x + 3) (y^{- 1} + 2)

e x t re m e f (x, y) = 11 x y + 5 x^{2}