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Beliebt Geometry >

16(x-1)^2+25(y-2)^2=400

Lösung

16 (x - 1)^{2} + 25 (y - 2)^{2} = 400

Lösung

(h, k) = (1, 2), a = 5, b = 4

Schritte zur Lösung

16 (x - 1)^{2} + 25 (y - 2)^{2} = 400

Rewrite

16 (x - 1)^{2} + 25 (y - 2)^{2} = 400

in the form of the standard ellipse equation

\frac{( x - 1 ) ^{2}}{5 ^{2}} + \frac{( y - 2 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, 2), a = 5, b = 4

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (1, 2), a = 5, b = 4

Graph

Beliebte Beispiele

x/(x^2+y^2)= 3/2

\frac{x}{x ^{2} + y ^{2}} = \frac{3}{2}

4x^2+25y^2-50y-75=0

4 x^{2} + 25 y^{2} - 50 y - 75 = 0

x^2+4y^2-2.71=0

x^{2} + 4 y^{2} - 2.71 = 0

((x-5)^2)/(144)+((y+2)^2)/(169)=1

\frac{( x - 5 ) ^{2}}{144} + \frac{( y + 2 ) ^{2}}{169} = 1

4y^{(2)}+2x^{(2)}-4y-8x-15=0

4 y^{(2)} + 2 x^{(2)} - 4 y - 8 x - 15 = 0