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cos(x)<0.5

Lösung

cos (x) < 0.5

\frac{π}{3} + 2 πn < x < \frac{5 π}{3} + 2 πn

Intervall-Notation

(\frac{π}{3} + 2 πn, \frac{5 π}{3} + 2 πn)

Dezimale

1.04719 \dots + 2 πn < x < 5.23598 \dots + 2 πn

Schritte zur Lösung

cos (x) < 0.5

Für

cos (x) < a

, wenn

- 1 < a \leq 1

dann

arccos (a) + 2 πn < x < 2 π - arccos (a) + 2 πn

arccos (0.5) + 2 πn < x < 2 π - arccos (0.5) + 2 πn

Vereinfache

arccos (0.5) : \frac{π}{3}

arccos (0.5)

= arccos (\frac{1}{2})

Verwende die folgende triviale Identität:

arccos (\frac{1}{2}) = \frac{π}{3}

arccos (\frac{1}{2})

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= \frac{π}{3}

= \frac{π}{3}

Vereinfache

2 π - arccos (0.5) : \frac{5 π}{3}

2 π - arccos (0.5)

arccos (0.5) = \frac{π}{3}

arccos (0.5)

= arccos (\frac{1}{2})

Verwende die folgende triviale Identität:

arccos (\frac{1}{2}) = \frac{π}{3}

arccos (\frac{1}{2})

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= \frac{π}{3}

= \frac{π}{3}

= 2 π - \frac{π}{3}

Vereinfache

2 π - \frac{π}{3}

Wandle das Element in einen Bruch um:

2 π = \frac{2 π 3}{3}

= \frac{2 π 3}{3} - \frac{π}{3}

Da die Nenner gleich sind, fasse die Brüche zusammen.:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 π 3 - π}{3}

2 π 3 - π = 5 π

2 π 3 - π

Multipliziere die Zahlen:

2 \cdot 3 = 6

= 6 π - π

Addiere gleiche Elemente:

6 π - π = 5 π

= 5 π

= \frac{5 π}{3}

= \frac{5 π}{3}

\frac{π}{3} + 2 πn < x < \frac{5 π}{3} + 2 πn

sin (2 x) < \frac{1}{2}

tan (x) \leq 1

4 cos (2 x) \geq 2, 0 \leq x < 2 π

sin (2 x) > cos (x)

cos (x) \leq 1