tan(t)=-12/5 ,(3pi)/2 <t<2pi

解答

tan (t) = - \frac{12}{5}, \frac{3 π}{2} < t < 2 π

t = - 1.17600 \dots + 2 π

度数

t = 292.61986 \dots^{\circ}

求解步骤

tan (t) = - \frac{12}{5}, \frac{3 π}{2} < t < 2 π

使用反三角函数性质

tan (t) = - \frac{12}{5}

tan (t) = - \frac{12}{5}

的通解

tan (x) = - a \Rightarrow x = arctan (- a) + πn

t = arctan (- \frac{12}{5}) + πn

t = arctan (- \frac{12}{5}) + πn

在

\frac{3 π}{2} < t < 2 π

范围内的解

t = - arctan (\frac{12}{5}) + 2 π

以小数形式表示解

t = - 1.17600 \dots + 2 π

3 sin (x) + 5 cos (x) = 4

3 + 2 cos (x) = 4 cos (\frac{x}{2})

- 3 sin (x) = cos (x)

2 csc^{2} (x) = 5 - 5 cot (x)

2 sin^{2} (x) = 3 sin (x)