5^{2x}=4

Lösung

5^{2 x} = 4

x = \frac{ln ( 2 )}{ln ( 5 )}

Dezimale

x = 0.43067 \dots

Schritte zur Lösung

5^{2 x} = 4

Wende Exponentenregel an

2 x ln (5) = ln (4)

Löse

2 x ln (5) = ln (4) : x = \frac{ln ( 2 )}{ln ( 5 )}

x = \frac{ln ( 2 )}{ln ( 5 )}

4^{- x} - 2^{- x + 2} + 4 = 0

x^{x} = \frac{1}{2}

7 e^{2 x + 3} = 20

4^{x} - 3 \cdot 2^{x + 2} + 32 = 0

27 = 3^{x + 1}