3^{2x+5}=3^7

Lösung

3^{2 x + 5} = 3^{7}

x = 1

Schritte zur Lösung

3^{2 x + 5} = 3^{7}

Wende Exponentenregel an

2 x + 5 = 7

Löse

2 x + 5 = 7 : x = 1

x = 1

e^{2 x} + e^{x} - 2 = 0

3 6^{2 x} = 21 6^{x - 1}

so l v e f or x, f = k a^{x}

2^{x^{2} - 1} = 4^{2 x + 2}

\frac{27}{( 3 ^{(1 - 3 x)} )} = 9