3^{2x+1}=7

Lösung

3^{2 x + 1} = 7

x = \frac{ln ( 7 ) - ln ( 3 )}{2 ln ( 3 )}

Dezimale

x = 0.38562 \dots

Schritte zur Lösung

3^{2 x + 1} = 7

Wende Exponentenregel an

(2 x + 1) ln (3) = ln (7)

Löse

(2 x + 1) ln (3) = ln (7) : x = \frac{ln ( 7 ) - ln ( 3 )}{2 ln ( 3 )}

x = \frac{ln ( 7 ) - ln ( 3 )}{2 ln ( 3 )}

\frac{27}{1 + e ^{- x}} = 2

2 7^{9^{x - 3}} = 33

8^{2 x - 1} = \frac{1}{2} 32

4^{x + 1} - 5 (2^{x}) + 1 = 0

2^{x - 1} = \frac{1}{4}