log_{3}(2x+2)=-2

Lösung

lo g_{3} (2 x + 2) = - 2

x = - \frac{17}{18}

Dezimale

x = - 0.94444 \dots

Schritte zur Lösung

lo g_{3} (2 x + 2) = - 2

Wende die log Regel an

2 x + 2 = \frac{1}{9}

Löse

2 x + 2 = \frac{1}{9} : x = - \frac{17}{18}

x = - \frac{17}{18}

lo g_{3} ((x - 1)^{2}) = 2

lo g_{3} (x - 4) = 1 + lo g_{9} (x)

ln (1 + x) = 1

ln (4 x) = 9

lo g_{2} (x + 2) - lo g_{2} (x - 1) = 4