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Beliebt Algebra >

faktorisieren 2x^5-9x^4+12x^3-4x^2-8x+4

Lösung

faktorisieren

2 x^{5} - 9 x^{4} + 12 x^{3} - 4 x^{2} - 8 x + 4

Lösung

(2 x - 1) (x^{2} - 2 x + 2) (x^{2} - 2 x - 2)

Schritte zur Lösung

2 x^{5} - 9 x^{4} + 12 x^{3} - 4 x^{2} - 8 x + 4

Wende den rationalen Nullstellentest an

= (2 x - 1) \frac{2 x ^{5} - 9 x ^{4} + 12 x ^{3} - 4 x ^{2} - 8 x + 4}{2 x - 1}

\frac{2 x ^{5} - 9 x ^{4} + 12 x ^{3} - 4 x ^{2} - 8 x + 4}{2 x - 1} = x^{4} - 4 x^{3} + 4 x^{2} - 4

= (2 x - 1) (x^{4} - 4 x^{3} + 4 x^{2} - 4)

Faktorisiere

x^{4} - 4 x^{3} + 4 x^{2} - 4 : (x^{2} - 2 x + 2) (x^{2} - 2 x - 2)

= (2 x - 1) (x^{2} - 2 x + 2) (x^{2} - 2 x - 2)

Beliebte Beispiele

8 = x^{2} - 8 x - 15

4 x^{2} - 200 = - 20

2 y^{2} + 10 y = - 7

(x-1)(x-2)(x-6)>0

(x - 1) (x - 2) (x - 6) > 0

faktorisieren 9x^2-9x+2

f a c t or 9 x^{2} - 9 x + 2