(dy)/(dx)=2tan^2(x)

Lösung

\frac{d y}{d x} = 2 tan^{2} (x)

y = 2 (- x + tan (x)) + c_{1}

Schritte zur Lösung

\frac{d y}{d x} = 2 tan^{2} (x)

Ersetze

\frac{d y}{d x}

mit

y^{'} (x)

y^{^{'}} (x) = 2 tan^{2} (x)

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int 2 tan^{2} (x) d x

\int 2 tan^{2} (x) d x = 2 (- x + tan (x)) + c_{1}

y = 2 (- x + tan (x)) + c_{1}

\int_{- 1}^{1} e^{- x^{2}} d x

x \to 0 lim (x^{\frac{1}{l n ( x )}})

\int 3 cos (n) x d x

n = 1 \sum \infty \frac{2}{1 + e ^{n}}

\frac{d}{d x} (\frac{( x - 3 )}{x + 3})