derivative g(x)=sqrt(1+2x)

Lösung

ableitung von

g (x) = 1 + 2 x

\frac{1}{1 + 2 x}

Schritte zur Lösung

\frac{d}{d x} (1 + 2 x)

Wende die Kettenregel an:

\frac{1}{2 1 + 2 x} \frac{d}{d x} (1 + 2 x)

= \frac{1}{2 1 + 2 x} \frac{d}{d x} (1 + 2 x)

\frac{d}{d x} (1 + 2 x) = 2

= \frac{1}{2 1 + 2 x} \cdot 2

Vereinfache

\frac{1}{2 1 + 2 x} \cdot 2 : \frac{1}{1 + 2 x}

= \frac{1}{1 + 2 x}

n = 1 \sum \infty (\frac{cos ( π )}{3})^{n}

\int_{0}^{\frac{π}{4}} sin^{3} (x) d x

\frac{\partial}{\partial y} (\frac{2 x}{x ^{2} + y})

16 y^{^{''}} + 8 y^{^{'}} + y = x + 6

y (x + 5) + y^{^{'}} = 0