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人気のある微分積分 >

integral from-1 to 0 of 3t^2e^{-t^3+1}

解

\int_{- 1}^{0} 3 t^{2} e^{- t^{3} + 1} d t

解

e^{2} - e

+1

十進法表記

4.67077 \dots

解答ステップ

\int_{- 1}^{0} 3 t^{2} e^{- t^{3} + 1} d t

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{- 1}^{0} t^{2} e^{- t^{3} + 1} d t

u置換積分法を適用する

= 3 \cdot \int_{2}^{1} - \frac{e ^{u}}{3} d u

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= 3 (- \int_{1}^{2} - \frac{e ^{u}}{3} d u)

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 (- (- \frac{1}{3} \cdot \int_{1}^{2} e^{u} d u))

共通積分を使用する:

\int e^{u} d u = e^{u}

= 3 (- (- \frac{1}{3} [e^{u}]_{1}^{2}))

簡素化

3 (- (- \frac{1}{3} [e^{u}]_{1}^{2})) : [e^{u}]_{1}^{2}

= [e^{u}]_{1}^{2}

限度を計算する:

e^{2} - e

= e^{2} - e

グラフ

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