laplacetransform 5sin(t)

Lösung

laplace transformation

5 sin (t)

\frac{5}{s ^{2} + 1}

Schritte zur Lösung

L {5 sin (t)}

Verwende die konstante Multiplikationseigenschaft der Laplace-Transformation:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 5 L {sin (t)}

L {sin (t)} : \frac{1}{s ^{2} + 1}

= 5 \cdot \frac{1}{s ^{2} + 1}

Fasse

5 \frac{1}{s ^{2} + 1}

zusammen:

\frac{5}{s ^{2} + 1}

= \frac{5}{s ^{2} + 1}

\int e^{t} + e^{- t} d t

\frac{\partial}{\partial z} (sin (x y))

\frac{\partial}{\partial y} (ln (\frac{y ^{9}}{x ^{7}}))

\int_{0}^{60} 25 e^{- 0.03 x} d x

\int \frac{9 t - 4}{t + 1} d t